11011 in binary is (1*2^4) + (1*2^3) + (0*2^2) + (1*2^1) + (1*2^0) = 16 + 8 + 0 + 2 + 1 = 27.
In hexadecimal, A represents 10. Thus, 1*16^1 + 10*16^0 = 16 + 10 = 26.
In octal, 77 = (7*8^1) + (7*8^0) = 56 + 7 = 63.
15 divided by 2 repeatedly gives 1111 in binary.
Group binary bits in threes from right: 101 and 010. 101 = 5, 010 = 2. Result is 52.
Octal system uses base 8, consisting of digits 0, 1, 2, 3, 4, 5, 6, and 7.
1111 = F in hex. 11111111 = FF.
20 divided by 16 is 1 with a remainder of 4. So, 14.
One hexadecimal digit ranges from 0 to F (0 to 15), which requires 4 bits (2^4 = 16).
In hexadecimal, the letters A, B, C, D, E, F represent decimal values 10, 11, 12, 13, 14, and 15 respectively.
1011 + 0110 = 10001 in binary (11 + 6 = 17 in decimal).
25 divided by 8 is 3 remainder 1, so 31 in octal.
Each F in hex is 1111 in binary, so FF is 11111111.
Octal 12 is 10 in decimal, which is A in hexadecimal.
Octal 5 is 101 and 4 is 100, so 54 is 101100.
Split 110101 into 0011 and 0101. 0011 is 3 and 0101 is 5.
1011 binary = 11, 12 octal = 10, A hex = 10, 10 decimal = 10. 11 is the largest.
Any base-n system has exactly n digits (0 to n-1).
10 hex is 16 decimal. 16 decimal in octal is 20 (2*8 + 0).
A=10, B=11, C=12, D=13.
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